Supports. This is the origin of the comparison. The post proves the weaker conditional bound in full and sketches a stronger one, and it is careful to say that both fall well short of Baker's theorem; the claim it actually argues for is that any proof of Collatz must use or replace transcendence theory, not that it would reprove Baker's theorem. Sep 16, 2026
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The Collatz conjecture, Littlewood-Offord theory, and powers of 2 and 311 passages
Conjecture 3 (Reformulated weak Collatz conjecture) There does not exist and integers8 passages
In particular, as is odd, . Using the recursion1 passage
Since , we have1 passage
Conversely, suppose that Conjecture 3 failed. Then we have , integers11 passages
The heuristic number of solutions overall is then expected to be4 passages
A brief computation shows that20 passages · 1 marked
This bound is very weak when compared against the unconditional bound (7) . However, I know of no way to get a nontrivial separation property between powers of and powers of other than via transcendence theory methods. Thus, this result strongly suggests that any proof of the Collatz conjecture must either use existing results in transcendence theory, or else must contribute a new method to give non-trivial results in transcendence theory. (This already rules out a lot of possible approaches to solve the Collatz conjecture.)
Supports. This is the origin of the comparison. The post proves the weaker conditional bound in full and sketches a stronger one, and it is careful to say that both fall well short of Baker's theorem; the claim it actually argues for is that any proof of Collatz must use or replace transcendence theory, not that it would reprove Baker's theorem.
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